Balanced parentheses using stacks

Balanced Parentheses Using Stacks

The logic that you used to solve the parenthesis problem using stacks is given below. $$String$$ is the argument string that is passed into the function.

Logic:

Declare a character stack $$S$.$

Traverse the expression string.

$-$ If the current character is $\text{'}(\text{'},$ push it into the stack.

$-$ If the current character is $\text{'})\text{'},$ pop it from the stack. If there is no $\text{'}(\text{'}$ to pop, throw an exception and return 'false'. If pop$()$ is called on an empty stack, then it indicates that the string is formed incorrectly.

$-$ If the stack is empty at the end, then it indicates that the string is formed correctly and return True

The method has given above returns 'True' if the algorithm if the string of parentheses is balanced; otherwise, it returns 'False'.

When you use this algorithm, what would be the state of the stack at its end if the string is as shown below?