Bars $AD,BC,CH,DI$& arm $()1$ of the lever are twice as long as bars $AE,EB,IJ,JH,IG,GH$ and arm FO respectively. Disregard the weight of the bars & the horizontal rod. The system is pinned at points $A,B,F,C,D,J,$I, $H$ and $E.$ What is the ratio between the weights $G_1$&$G_2$ if the system shown in figure is in equilibrium?

$($A$)\frac{G_1}{G_2}=\frac{2}{3}$

$($B$)\frac{G_1}{G_2}=\frac{3}{2}$

$($C$)\frac{G_1}{G_2}=\frac{1}{2}$

$($D$)\frac{G_1}{G_2}=2$