Question: / / Base case: if the node is null, the subtree is complete if ( node = = null ) { return true; } /

// Base case: if the node is null, the subtree is complete if (node == null){ return true; }// If the index is greater than or equal to the number of nodes, it's not complete if (index >= totalNodes){ return false; }// Recursively check the left and right subtrees // Left child index =2* index +1// Right child index =2* index +2 return isComplete(node.left, 2* index +1, totalNodes) && isComplete(node.right, 2* index +2, totalNodes);

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