Based on a careful work study in the Richard Dulski$$ Corp., the results shown in the following table have been$$ observed:

Element Observation $1$ Observation $2$ Observation $3$ Observation $4$ Observation $5$ Performance Rating

Prepare daily reports $3540334138120\%$

Photocopy results $1211371612115\%$

Label and package reports $4454590\%$

Distribute reports $141720184490\%$

Photocopying the results during observation $3$ was influenced by the photocopying machine being broken. Distributing the reports during observation $5$ was influenced by a power outage. Both of these are included as delays in the allowance factor.

The allowance factor for this type of work is given to be $15\%.($Round all intermediate calculations to two decimal places before proceeding with further$$ calculations.$)$

Part $2$

$$a$)$ The normal time for the$$ "prepare daily$$ reports" operation$=$

$$

enter your response here minutes. $($Round your response to two decimal$$ places.$)$

Part $3$

The normal time for the$$ "photocopy results" operation$=$

$$

enter your response here minutes. $($Round your response to two decimal$$ places.$)$

Part $4$

The normal time for the$$ "label and package$$ reports" operation$=$

$$

enter your response here minutes. $($Round your response to two decimal$$ places.$)$

Part $5$

The normal time for the$$ "distribute reports" operation$=$

$$

enter your response here minutes. $($Round your response to two decimal$$ places.$)$

Part $6$

The normal time for the overall process$=$

$$

enter your response here minutes. $($Round your response to two decimal$$ places.$)$

Part $7$

$$b$)$ The standard time for this process$=$

$$

enter your response here minutes. $($Round your response to two decimal$$ places.$)$

Part $8$

$$c$)$ The number of observations that are required for a $99\%$ confidence level within $5\%$ accuracy$=$

$$

enter your response here. $($Round your response to the immediate higher whole$$ number.$)$