based on the below algorithm fill in the rest of the below code

Choose a random glossary key

Choose another random glossary key

Decide randomly whether to display the correct or incorrect definition

Display the random glossary key

Display either the correct or incorrect definition, as appropriate

Ask the user if key and the definition is correct

If correct definition was displayed and user evaluate it as correct, display user answer is correct

If incorrect definition was displayed and user evaluate it as incorrect, display user answer is correct

else display user answer is incorrect

repeat until user quits

Python code:

def show_flashcard():

"""

ADD YOUR DOCSTRING HERE

"""

""" Do not change this first section."""

# Get glossary keys.

keys = list(glossary)

# Choose two distinct keys at random.

sample_keys = sample(keys, 2)

# The first is the entry that will be displayed.

# The definition corresponding to this is the right one.

random_entry = sample_keys[0]

# The second entry will not be displayed.

# The definition corresponding to this is the wrong one.

other_random_entry = sample_keys[1]

# This variable will control whether the user is

# shown the right definition or the wrong one.

right_or_wrong = choice(['right', 'wrong'])

# Pose question.

print('Here is a glossary entry:')

print(random_entry)

print('Here is a possible definition for it:')

if right_or_wrong == 'right':

print(glossary[random_entry])

else:

print(glossary[other_random_entry])

""" End of first section."""

""" Insert your code below."""

""" Do not change anything beyond this point """

# Set up the glossary

glossary = {'word1':'definition1',

'word2':'definition2',

'word3':'definition3'}

# The interactive loop

exit = False

while not exit:

user_input = input('Enter s to show a flashcard and q to quit: ')

if user_input == 'q':

exit = True

elif user_input == 's':

show_flashcard()

else:

print('You need to enter either q or s.')