Based on the pumping lemma, if$$L$$is regular, then$$k$1($strings$$w$$ in $$L$,$ where $|$w$|$k$($x$,$y$,$z$($w$=$xyz$,|$xy$|$k$,$y$,$ and$$q$0($xyqz$$is in$$L$)))).$

The correct statements are:

Group of answer choices

For$$L$=$ab$*$ab$,$ let$$k$=4$ and every string$$w$$in$$L$$with $|$w$|$k$$must be pumpable.

For$$L$=$ab$*$ab$,$ let$$k$=3$ and every string$$w$$in$$L$$with $|$w$|$k$$must be pumpable.

For$$L$=$ab$*$ab$,$ let$$k$=2$ and every string$$w$$in$$L$$with $|$w$|$k$$must be pumpable.

For$$L$=$ab$*$ab$,$ let$$k$=5$ and every string$$w$$in$$L$$with $|$w$|$k$$must be pumpable.