Question: BE 1 2 1 . Liquid Mn Fe 1 8 6 3 K XMn = 0 . 6 Gibbs Gxs = 1 0 5

BE12"1.Liquid Mn Fe 1863 K XMn =0.6 Gibbs Gxs =1055 J/mol
a ''
Mn
c Fe
d
e "

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