Question: ( begin{array}{c}left(frac{-2}{3}, frac{2 sqrt{3}}{3} ight) f(x)=-3 x sqrt{x+1} f^{prime}left(frac{-2}{3} ight)=end{array} )
\\( \\begin{array}{c}\\left(\\frac{-2}{3}, \\frac{2 \\sqrt{3}}{3}\ ight) \\\\ f(x)=-3 x \\sqrt{x+1} \\\\ f^{\\prime}\\left(\\frac{-2}{3}\ ight)=\\end{array} \\)
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