Question: ( begin{array}{l}text { price }=178+0.47 B D R+17.8 text { Bath }+325 operatorname{Ln}(text { Hsize })+107 text { adjusted } R^{2}=0.7end{array} )

\\( \\begin{array}{l}\\text { price }=178+0.47 B D R+17.8 \\text { Bath }+325 \\operatorname{Ln}(\\text { Hsize })+107 \\\\ \\text { adjusted } R^{2}=0.7\\end{array} \\)

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