Question: ( begin{array}{l}u=2 t- d u=2 d x 2 int cos (u) 2 sin (u) 2 sin left(frac{pi}{12} ight)^{frac{pi}{2} 2 cos (2

\\( \\begin{array}{l}u=2 t- \\\\ d u=2 d x \\\\ 2 \\int \\cos (u) \\\\ 2 \\sin (u) \\\\ 2 \\sin \\left(\\frac{\\pi}{12}\ ight)^{\\frac{\\pi}{2} 2 \\cos (2 t)}-2 \\sin (0) \\\\ 2.1-2.0 \\\\ 2-0=2\\end{array} \\)

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