Bethany used the steps below in an attempt to solve for angle B in triangle ABC. In triangle A B C, sides A B, A C, and B C are 4 point 5 centimeters, 4 point 1 centimeters, and 2 point 7 centimeters long respectively. The figure is not drawn to scale. 4.1 squared equal to 4.5 squared plus 2.7 squared minus 2 (4.5) (2.7) cosine B line break 4.1 equal to 4.5 plus 2.7 minus 24.3 cosine B line break minus 3.1 equal to minus 24.3 cosine B line break 0.1276 equal to cosine B line break B equal to 82.7 Where is Bethany's error? Bethany made one side of the equation equal to the square of the incorrect side when solving for B. Bethany took the square root of each squared term before isolating cosB and solving for B. Bethany used cosine instead of inverse cosine when finding B. Bethany neglected to multiply the expression involving the cosine by 2