Question: (b)g(x) is increasing for x <3 and decreasing x>3, continuous everywhere, and has a cusp at x=3.limh0-g(3h)-g(3)h=limh0g(3h)-g(3)h=

(b)g(x) is increasing for x<3 and decreasing x>3, continuous everywhere, and has a cusp at x=3.limh0-g(3h)-g(3)h=limh0g(3h)-g(3)h=

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