Question: Binary Bomb Lab - Phase 2: (x86 assembly) I know that this stage takes an input of 6 numbers (ex. 1 2 3 4 5
Binary Bomb Lab - Phase 2: (x86 assembly)
I know that this stage takes an input of 6 numbers (ex. 1 2 3 4 5 6). The first number is one. I get confused reading the assembly and can't figure out the other steps using the gdb. Could someone translate the assembly and explain the code in simple terms for me, please?

read_six_numbers function:

400f73: 400f74: 400f77 400f79: 400f7a push mov push push sub Lea callq pl je callq lea lea mov add p je callq 48 89 e5 41 54 53 48 83 ec 20 48 8d 75 de %rbp %rsp, %rbp %r12 %rbx $6x29 , % rsp -0x39 (%rbp) ,%rsi 40f82 : 40f87 : 400f8b: 400f8d: 400f92: 400f96: 400f9a: 400f9c 400f9e: 400fal: 400fa3: 400fa8: 400fac: 400faf: 400fbl: 400fb5: 400fb6: 400fb8: 400fb9: 4016a4
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
