BIUV v ab X x AvLAV E Styles Styles Dictate Sensitivity Pane 4) Explain why N 2 0 and K 2 0 for every n. Use these inequalities and the expressions for N and K in problem 2 to find an upper bound for the number of cycles, and an upper bound for the number of K ions inside the cell, based on the number of available Nat ions in the cell. Show your work and interpret your results.Pane 2) Let n represent the number of cycles, as defined in problem 1. In addition, let No and Ko represent the initial number of Nat and K+ ions, respectively, inside the cell before the first cycle starts. Complete the following table to derive equations for the number of Nat and K ions remaining inside the cell after n cycles. n Number of Nations Number of K+ ions No - 3 Ko + 2 No - 6 Ko + 4 W / N No - 9 Ko + 6 No - 12 Ko + 8 No - 3( -15 ) Ko + 2( 10 ) No - 3(-18 ) Ko + 2(12 ) After n cycles, the number of Nat ions inside the cell is N (n) = _No - 3n and the number of K+ ions inside the cell is K (n) =_ Ko + 2n