Question: * = - biv b2 - 4ac ex. * 2 + 6* + 5 a = 1 6= 6 0= 5 * * - (

* = - biv b2 - 4ac ex. * 2 + 6* + 5 a = 1 6= 6 0=
* = - biv b2 - 4ac ex. * 2 + 6* + 5 a = 1 6= 6 0= 5 * * - ( 6 ) + 16) 2 - (4) (1 ) 15 ) 2 (1 ) -6 + 1/36- 20 2 - 6 + 1/ 16 2 X = - 6 + 4 2 * = - 6+ 4 - 2 2 2 ( x = 1 - 6 - 4 X = - 10 2 2 * =-5

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