blue car with mass m c = 443 kg is moving east with a speed of v

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Question:

blue car with mass m_c = 443 kg is moving east with a speed of v_c = 23 m/s and collides with a purple truck with mass m_t = 1214 kg that is moving south with a speed of v_t = 12 m/s . The two collide and lock together after the collision.

1)What is the magnitude of the initial momentum of the car? _kg-m/s

2)What is the magnitude of the initial momentum of the truck? _kg-m/s

3)What is the angle that the car-truck combination travel after the collision? (give your answer as an angle South of East) _

4)What is the magnitude of the momentum of the car-truck combination immediately after the collision? _kg-m/s

5)What is the speed of the car-truck combination immediately after the collision? _m/s

6)Compare the initial and final kinetic energy of the total system before and after the collision: KE_i = KE_f

KE_i > KE_f

KE_i < KE_f

A train car with mass m₁= 587 kg is moving to the right with a speed of v₁= 7.2 m/s and collides with a second train car. The two cars latch together during the collision and then move off to the right at v_f= 4.6 m/s.

1)What is the initial momentum of the first train car? _kg-m/s

2)What is the mass of the second train car? _kg

3)What is the change in kinetic energy of the two train system during the collision? _J

4)Now the same two cars are involved in a second collision. The first car is again moving to the right with a speed of v₁= 7.2 m/s and collides with the second train car that is now moving to the left with a velocity v₂= -5.4 m/s before the collision. The two cars latch together at impact.

What is the final velocity of the two-car system? (A positive velocity means the two train cars move to the right - a negative velocity means the two train cars move to the left.) _m/s

5)Compare the magnitude of the momentum of train car 1 before and after the collision: p_{1 initial}= p_{1 final}

p_{1 initial}> p_{1 final}

p_{1 initial}< p_{1 final}