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D Question 29 3 pts We suspect that Method 1 for detecting impurities in iron ingots yields higher results than Method 2 for finding such impurities. We want to give a 90% confidence interval for the difference in the average number of impurities detected by the two methods. In order to obtain the confidence interval, we measured the impurities of 3 ingots, employing both methods for each ingot. The results are presented in the table below. We let /1 denote the population average number of defects for Method 1 and /2 denotes the population average number of defects for Method 2. We wish to develop a confidence interval for /d = /1 - /2 Give the margin of error for the 90% confidence interval for Mad = M1 - /2 Ingot 1 Ingot 2 Ingot 3 Method 16 32 12 Method 2 12 26 10 O 1.84 O 4.97 O 3.37 O 1.90 O 2.26 D Question 30 3 pts We wish to give a 90% confidence interval for /. Here, / denotes the mean value of a normally distributed random variable Y. In order to develop this confidence interval we have obtained a random sample of 5 elements from the population on which Y is defined. The data for the sample are Y=8,12,14,16,20. Give the margin of error for the 90% confidence interval for /. O 3.290 O 3.92 O 14 O 4.264 O 2.132