Question: both question PE = mgh KE = 1/2 m v2 ME = PE + KE 1. A skateboarder is at the top of a hill

both question

PE = mgh KE = 1/2 m v2 ME = PE + KE 1. A skateboarder is at the top of a hill with a height of 50m. The skateboarder has a weight of 70kg and is initially at rest (velocity = 0 m/s). When the skateboarder gets to the bottom of the hill that has a height of 50m he has a velocity of 31.3 m/s. * *Show your work for all problems** a. What is the PE of the skateboarder at the top of the hill? (Reminder: g= 9.8 m/s/s) 34300 m/s b. What is the KE of the skateboarder at the top of the hill

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