Box one says reject or do not rejectBox two says provide or do not provideBox 3 says different from, greater than, the same as, less than

Suppose a study reported that the average person watched 5.51 hours of television per day. A random sample of 15 people gave the number of hours of television watched per day shown. At the 1% 4.7 2.0 4.3 9 significance level, do the data provide sufficient evidence to conclude that the amount of television watched per day last year by the average person differed from the value reported in the study? (Note: 2.7 4.7 x =4.347 hours and s = 1.310 hours.) 3.6 5.1 4.1 5.0 CO 5.3 5.0 4 8 Click here to view a partial table of values of to . Set up the hypotheses for the one-mean t-test. Ho : H Ha: H The test statistic is t=] (Round to two decimal places as needed.) Identify the critical value(s). Select the correct choice below and fill in the answer box within your choice. (Round to three decimal places as needed.) O A. The critical value is to = O B. The critical value is - to = O C. The critical values are to/2 = + sufficient evidence to conclude that the amount of television watched by the average person is the value reported in the study. the null hypothesis. The data