Bullets from two revolvers are fired with the same velocity. The bullet from gun $\backslash$#$1$ is twice as heavy as the bullet from gun $\backslash$#$2.$ Gun $\backslash$#$1$ weighs three times as much as gun $\backslash$#$2.$ The ratio of the momentum imparted to gun $\backslash$#$1$ to that imparted to gun $\backslash$#$2$ is

$2$:$3$

$6$:$1$

$\backslash (3$: $2\backslash )$

$2$:$1$

$3$:$1$