By considering different paths of approach, show that the function below has no limit as (x,y) (0,0). h(x,y)= Examine the values of h along curves that end at (0,0). Along which set of curves is h a constant value? OA. y=kx+kx2, x 0, k #0 OB. y=kx3, x#0, #0 OC. y=kx2, x 0, k#0 OD. y=kx, x 0, k 0 If (x,y) approaches (0,0) along the curve when k = 1 used in the set of curves found above, what is the limit? (Simplify your answer.) If (x,y) approaches (0,0) along the curve when k = 2 used in the set of curves found above, what is the limit? (Simplify your answer.) What can you conclude? A. Since f has two different limits along two different paths to (0,0), it cannot be determined whether or not f has a limit as (x,y) approaches (0,0). B. Since f has two different limits along two different paths to (0,0), by the two-path test, f has no limit as (x,y) approaches (0,0). C. Since f has the same limit along two different paths to (0,0), by the two-path test, f has no limit as (x,y) approaches (0,0). D. Since f has the same limit along two different paths to (0,0), it cannot be determined whether or not f has a limit as (x,y) approaches (0,0)