By using the standard normal distribution table you provided, we can estimate the percentile rank for a Z-score of approximately 0.7295. Looking at the table, we see that for a Z-score of 0.72, the value is approximately 0.7642, and for a Z-score of 0.73, the value is approximately 0.77337. Since 0.7295 falls between these two values, we can estimate that the percentile rank for a Z-score of approximately 0.7295 is around 76.24% (closer to the 0.72 Z-score value of 0.7642). the estimated percentile rank for a Z-score of approximately 0.7295 is around 76.24%. What is the probability that a score with this value, or higher, would be found in the population by chance