$C^2[S](1,1$:$7,\frac{1}{2})(2,2$:$2,2)(3,1$:$6,\frac{3}{2})(4,3$:$6,\frac{2}{3})(5,2$:$5,\frac{1}{2})$ out

Note: the processing time $isin$ minutes. The inflow rate $is8$ job$\frac{s}{h}r.$ with $anSCVof\frac{3}{2.}$

There are $2$ machines $inWS1,$ and $1$ machine each $in$ the other two workstations. Fill $in$ the

data for the following analysis $of$ the factory performance.

Average Product Workstation Model Data:

Inflow rates: $(6$ points$)$

$(?,?,?)$

Avg. Product $E[\frac{?}{\text{b}\text{a}\text{r}}(S{)}_i]$: $(3$ points$)$

$(?,0\mathrm{.}0583,0\mathrm{.}1000)$

Avg. Product $C^2[\frac{?}{\text{b}\text{a}\text{r}}(S_i)]$: $(3$ points$)$

$(?,1\mathrm{.}0204,\frac{2}{3})$

Avg. Product Branching Probabilities Matrix: $(3$ points$)$

$\frac{?}{\text{b}\text{a}\text{r}}(P)=\left[\begin{array}{ccc}0& 0\mathrm{.}5& ?\\ ?& 0& 0\\ 0& 1& 0\end{array}\right]$

Write the SCVa$(1)$ equation for Workstation $1$: $(10$ points$)$

Assume that the SCVa results are: $(1\mathrm{.}2513,0\mathrm{.}9028,1\mathrm{.}0140)$ and complete the remaining

analysis. Avg. Product Workstation Performances Measures: $(12$ points$)$

Factory Performance Measures:

THfac: $(2$ points$)$

WIPfac: $(3$ points$)$

CTfac: $(3$ points$)$

Show that the CTfac $=CTsys(Prod1)$: $(10$ points$)$