Question: C. 33 VIRTUAL MEMORY } Virtual page Virtual address space 60K BAK X 56K-GOK TX 52K_56K 48K-52K 446-48K 40K-44K 36K 40K 5 32K-36K 28K-32KXi 24K-28K



C. 33 VIRTUAL MEMORY } Virtual page Virtual address space 60K BAK X 56K-GOK TX 52K_56K 48K-52K 446-48K 40K-44K 36K 40K 5 32K-36K 28K-32KXi 24K-28K 20K 24K 3 16K-20K 12K-16KO 8-12K 4K-8K OK-4K Physical memory address 28K-32K 24K-28K 20K-24K 16K-20K 12K-16K 8-12K 4K-8K OK-4K Page frame Figure 3-9. The relation between Virtual addresses and physical memory ad- dresses is given by the page table. Every page begins on a multiple of 4096 and ends 4095 addresses higher so K-8K really means 4096-8191 and 8K to 12K means 8192-12287 * page and for an 8 KB page: 20000, 32768, 60000. Using the page table of Fig. 3-9, give the physical address corresponding to each of the following virtual addresses (a) 20 (b) 4100 (c) 8300 45. Explain the difference between internal fragmentation and external fragmentation. Which one occurs in paging systems? Which one occurs in systems using pure seg- mentation
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