Question: C++ 5:30 Snapchat LTE x CSDP250 Fall 201 CSDP250 Fall, 2018 Program 01 due: September 7, 2018 This completed program (cpp file only) to albertcasavant@gmail.com

C++
 C++ 5:30 Snapchat LTE x CSDP250 Fall 201 CSDP250 Fall, 2018
Program 01 due: September 7, 2018 This completed program (cpp file only)

5:30 Snapchat LTE x CSDP250 Fall 201 CSDP250 Fall, 2018 Program 01 due: September 7, 2018 This completed program (cpp file only) to albertcasavant@gmail.com with the subject line: 250 Program program is an exercise in using pointers Pass in your For this program you function do something and print out some results will declare some variables in main, call a outside of main declare a constant integer SIZE outside of main and initialize it to 6 declare constant doubles named one, two, three, four, five, six initialized to 1.0, 2.0, 3.0, 4.0, 5.0, 6.0, respectively in main Declare a dynamic array (using new) of pointers to doubles of size SIZE. Name the array dynamic arr ptrs to dbl. (Notice here that the contents of the array are pointers, so the array is an array of pointers to doubles. Since this is an exercise in using pointers, use pointer notation rather than square bracket notation Declare an alias to the dynamic array called dynamic arr ptrs to dbl alias Declare a pointer to an integer called size ptr and initialize it to be a reference to SIZE Declare a static array of pointers to doubles called static arr ptrs to dbl of size SIZE and initialize it to be references to the one, two, three, four, five, six constants you declared above. (Since this is an exercise in using pointers, use pointer notation rather than square bracket notation wherever Call a function do something (described below) using the call: double *returned pointer - do something (dynamic _arr ptrs to dbl alias, static arr ptrs to dbl, size ptr) Notice that the function returns a pointer to a pointer to double. This is necessary because the argument dynamic arr ptrs to dbl alias to function do something was

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