Zn electrode 1 Zn+ (aq) (1 M) Salt bridge Fe2+ A B I = (aq) (1...

 

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Zn electrode 1 Zn²+ (aq) (1 M) Salt bridge Fe2+ A▾ B I = (aq) (1 M) The spontaneous reaction for this Voltaic cell is Zn²+ (aq) + Fe(s) → Zn(s) + Fe²+ (aq) Reduction potential data: Zn²+ (aq) + 2e → Zn(s) - 0.76 V Fe2+ (aq) + 2e-Fe(s) -0.44V 1.Calculate the Eºcell (showing your working). 2.Describe the direction of electron flow when the reaction proceeds. Menu arrow above - Click this for more formatting. 1. Calculate the Eºcell (showing your working). Fe electrode 2. Describe the direction of electron flow when the reaction proceeds. Zn electrode 1 Zn²+ (aq) (1 M) Salt bridge Fe2+ A▾ B I = (aq) (1 M) The spontaneous reaction for this Voltaic cell is Zn²+ (aq) + Fe(s) → Zn(s) + Fe²+ (aq) Reduction potential data: Zn²+ (aq) + 2e → Zn(s) - 0.76 V Fe2+ (aq) + 2e-Fe(s) -0.44V 1.Calculate the Eºcell (showing your working). 2.Describe the direction of electron flow when the reaction proceeds. Menu arrow above - Click this for more formatting. 1. Calculate the Eºcell (showing your working). Fe electrode 2. Describe the direction of electron flow when the reaction proceeds.

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ll Now 2 ZO aq Fers 2n 2p x 2e Fe Fe 2 ae O E Ered c 076 1 1 035 v Zn s Fe2 EO 076 ... View the full answer