Question: C code: B[8] = g + A[12] , where g in $s5, base addressed for A and B are in $s0 and $s1 respectively. How

C code: B[8] = g + A[12], where g in $s5, base addressed for A and B are in $s0 and $s1 respectively. How many data transfers instructions have to be involved for compiled MIPS codes?

*The answer is 2 but I don't know why. Can someone please explain?

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