Question: C. Construct another two-way contingency table (crosstabulation) and find the expected frequency for each cell. Preference * Gender Crosstabulation Gender Female Male Total Preference Dark

 C. Construct another two-way contingency table (crosstabulation) and find the expected

frequency for each cell. Preference * Gender Crosstabulation Gender Female Male Total

C. Construct another two-way contingency table (crosstabulation) and find the expected frequency for each cell. Preference * Gender Crosstabulation Gender Female Male Total Preference Dark Count 8 25 33 Expected Count 11.2 21.8 33.0 Light Count 39 51 90 Expected Count 30.6 59.4 90.0 Regular Count 21 56 77 Expected Count 26.2 50.8 77.0 Total Count 68 132 200 Expected Count 68.0 132.0 200.0 D. Check whether each expected frequency is at least 5. Each expected frequency is more than 5. The minimum expected count is 11.22 . E. State Ho and Ha. F. At the 5% significance level, perform a hypothesis test to determine whether beer drinkers' preferences depend on their gender

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