Question: C++: Giving the function prototype and variable declaration in the picture Why is tryOut (a+ b, 'b', b, y); a valid function call? Justification please!

C++:

Giving the function prototype and variable declaration in the picture

C++: Giving the function prototype and variable declaration in the picture Why

Why is "tryOut (a+ b, 'b', b, y);" a valid function call? Justification please!

void tryout (int, char, int&, float&); int a 4, b 0; //variable declarations float y, char c; function prototype

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