Question: C++: #include using namespace std; string ltrim(const string &); string rtrim(const string &); /* * Complete the 'isPossible' function below. * * The function is

C++:

C++: #include using namespace std; string ltrim(const string &); string rtrim(const string

#include

using namespace std;

string ltrim(const string &);

string rtrim(const string &);

/*

* Complete the 'isPossible' function below.

*

* The function is expected to return a STRING.

* The function accepts following parameters:

* 1. INTEGER a

* 2. INTEGER b

* 3. INTEGER c

* 4. INTEGER d

*/

string isPossible(int a, int b, int c, int d) {

}

int main()

{

ofstream fout(getenv("OUTPUT_PATH"));

string a_temp;

getline(cin, a_temp);

int a = stoi(ltrim(rtrim(a_temp)));

string b_temp;

getline(cin, b_temp);

int b = stoi(ltrim(rtrim(b_temp)));

string c_temp;

getline(cin, c_temp);

int c = stoi(ltrim(rtrim(c_temp)));

string d_temp;

getline(cin, d_temp);

int d = stoi(ltrim(rtrim(d_temp)));

string result = isPossible(a, b, c, d);

fout

fout.close();

return 0;

}

string ltrim(const string &str) {

string s(str);

s.erase(

s.begin(),

find_if(s.begin(), s.end(), not1(ptr_fun(isspace)))

);

return s;

}

string rtrim(const string &str) {

string s(str);

s.erase(

find_if(s.rbegin(), s.rend(), not1(ptr_fun(isspace))).base(),

s.end()

);

return s;

}

Consider a pair of integers, (a, b). The following operations can be performed on (a, b) in any order, zero or more times: (a, b) = (a + b, b) (a, b) (a, a + b) Return a string that denotes whether or not (a, b) can be converted to to (c, d) by by performing zero or more of the operations specified above

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