Question: C++ LANGUAGE /** * Given an input string, count the number of words ending * in 'y' or 'z' -so the 'y' in heavy and

C++ LANGUAGE

/**

* Given an input string, count the number of words ending

* in 'y' or 'z' -so the 'y' in "heavy" and the 'z' in "fez"

* count, but not the 'y' in "yellow". Make sure that your

* comparison is not case sensitive. We'll say that a y

* or z is at the end of a word if there is not an alphabetic

* letter immediately following it.

*

* Do not use any string functions except for substr(),

* at(), and size(). You may use isalpha from cctype as well.

*

*

* Here are some other examples:

* - "fez day" -> 2

* - "day fez" -> 2

* - "day fyyyz" -> 2

*/

int endzy(const string& str)

{

int result;

// Your code goes here

return result;

}

I WILL VOTE THUMB IF ALL PASS

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