$cos{}_{c}t=\frac{1}{2}[e^{j{}_{c}t}+e^{-j{}_{c}t}]$

and

$sin{}_{c}L=\frac{1}{2}[e^{j{}_{c}t}-e^{-j{}_{c}t}]$

prove, that we can write

prove, that $we$ xos${}_{c}t-x_2(t)sin{}_{c}t=R(t)*cos[{}_{c}t+]$

$x_1(t)cos$ faster than $x_1(t)$ ave

providing $cos{}_{c}t$ is much faster than $x_1(t)$ and $x_2(t).$ Solve it by hand writing please