c++ Please correct my code: How can I pass user input from void Date::Input(int &Test) { int d, y; cout < >Test; cout < >d;

c++

Please correct my code:

How can I pass user input from

void Date::Input(int &Test) { int d, y; cout<<"Enter Month: "; cin>>Test; cout<<"Enter Day: "; cin>>d; cout<<"Enter Year: "; cin>>y; if (Test < 1 || Test > 12 || d < 1 || d > 31 || y < 1583) { cout << "Invalid date entered. Using default date: 1/1/2000"< 
To
 
 
 
void Date::Show() { cout<<"Default:"< 
string Date::MonthHelper(int number) { string mth; switch (number) { case 1: mth = "Jan"; break; case 2: mth = "Feb"; break; case 3: mth = "March"; break; case 4: mth = "April"; break; case 5: mth = "May"; break; case 6: mth = "June"; break; case 7: mth = "July"; break; case 8: mth = "Aug"; break; case 9: mth = "Sep"; break; case 10: mth = "Oct"; break; case 11: mth = "Nov"; break; case 12: mth = "Dec"; break; } return month_; }
 
 
 
For reference:
 
kindly note that I have created a class called Date:
 
class Date { private: int month; int day; int year; public: void Input(int &); void Show(); string MonthHelper(int); };
 
Main goal is to display date in 4 forms:
 
 
 
 
 
Name
 
 
 
Format
 
 
 
Example
 
 
 
Explanation
 
 
 
 
 
Default
 
 
 
M/D/Y
 
 
 
10/4/1998
 
 
 
This will look like the input from the Input function. Print the month, day, and year as integer values.
 
 
 
 
 
Two-Digit
 
 
 
mm/dd/yy
 
 
 
10/04/98
 
 
 
Fixed size format, in which the month, day, and year values are always 2 digits Some values may need to be padded with a leading zero, and year values always show the low 2 digits.
 
 
 
 
 
Long
 
 
 
month D, Y
 
 
 
Oct 4, 1998
 
 
 
This display format should show the abbreviated month name, then the day, and the full year. Month abbreviations are Jan, Feb, Mar, Apr, May, June, July, Aug, Sept, Oct, Nov, and Dec
 
 
 
 
 
Julian
 
 
 
DDD, Y
 
 
 
123, 2001
 
 
 
This displays the Julian Date format. 123 in the Year 2001 is actually May 3rd, 2001. Leading edge zeros are not required.