Question: c programming CHALLENGE ACTIVITY 4.11.1: Floating-point comparison: Print Equal or Not equal. Write an expression that will cause the following code to print Equal if

c programming CHALLENGE ACTIVITY 4.11.1: Floating-point comparison: Print Equal or Not equal.c programming

CHALLENGE ACTIVITY 4.11.1: Floating-point comparison: Print Equal or Not equal. Write an expression that will cause the following code to print "Equal" if the value of sensor Reading is "close enough" to targetValue. Otherwise, print "Not equal". Ex: If targetValue is 0.3333 and sensorReading is (1.0/3.0), output is: Equal 1 #include 2 #include 3 4 int main(void) { 5 double targetValue; 6 double sensorReading; 7 8 scanf("%1f", &targetValue); 9 scanf("%16", &sensorReading); 10 11 if (* Your solution goes here */) { 12 printf("Equal "); 13 } 14 else { 15 printf("Not equal "); 16 } 17 18 return; 19} Run

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Databases Questions!