c++

Re-write the given function, printSeriesSkipThree, to use a for loop (instead of while). The function takes a single integer n as a parameter The function prints a series between 1 and that integer parameter (inclusive) and also prints its result The result is calculated by adding all numbers between 1 and the input integer parameter except for the numbers that are divisible 3 The function does not return a value. The series is: 1 + 2 + 0 + 4 +5 + 0 + 7 + 8 + 0 + 10 + 11 + 0 + 13 + 14 + 0 + 16 + .... Example 1: Calling function with the integer 5 should print the following: 1 + 2 + 0 + 4 + 5 Result of the series is 12 Example 2: Calling function with the integer 10 should print the following: 1 + 2 + 0 + 4 + 5 + 0 + 7 + 8 + 0 + 10 Result of the series is 37 void printSeriesSkipThree(int maxValue) { int sum = 0; int i = 1; while (i