Question: C Some definitions for the test. A = [5,7,2, 9, 1, 3, 4, 3, 5, 8, 7,3) B = [5,8,3,5,9,5,4,7,1,0,5,7,8] C=[W, X, Y,A, B,M, N,
![3, 4, 3, 5, 8, 7,3) B = [5,8,3,5,9,5,4,7,1,0,5,7,8] C=[W", X, "Y","A",](https://dsd5zvtm8ll6.cloudfront.net/si.experts.images/questions/2024/09/66f3ca13b70d3_01166f3ca1357f04.jpg)
C Some definitions for the test. A = [5,7,2, 9, 1, 3, 4, 3, 5, 8, 7,3) B = [5,8,3,5,9,5,4,7,1,0,5,7,8] C=[W", X, "Y","A", "B","M", "N", ""] D= ["A", "B", "C" "Z","G","M", "T", "W" 1 E=3 F="ABCDEFGH G="F" Hes V = [[4,5,6). [4,31(1,2,31.14,5,6,7,81,17,8,911 W "ABCJKLMNTVWXYZ" X = "PQRSTUVW Y=1["A", "B", "C" LET","R" L ["D", "E", "F" 11 W,X,Y,Z1[*G","H11 Z = 23.658 Coin - [H, T1 Die = [1,2,3,4,5,6] Starter = 1 Blank" Alph=["A", "B", "C", "O". V", "W", X, Y, Z1 "F", "G", "H",7,7 *S*, T. "U" Each expression evaluation begins from these definitions. Any alterations during the evaluation of the expression is lost after the conclusion of the evaluation of that expression, although the alteration does hold in effect until the end of that evaluation QUESTION 26 slice(F, 2,5) == "CDEF QUESTION 27 slice(F. 2.5) concat("CD", "EP") QUESTION 28 join(C. QUESTION 29 charAt(join(C.-7.5) - "B" CUFSTION 30
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