c++

Write a program that outputs a technicians utilization

The following information will be known:

F=failure rate of machines R=number of technicians hired

T=traffic intensity = F/U N=total number of machines

W=hourly wage of technician ($/hr) L=cost of inoperative machines ($/hr)

U=repair rate of technicians (note that this is lower for faster technicians)

The basic problem is to minimize total cost. The total cost includes the cost of the technicians plus the cost of having machines down:

Cost=(#techs)(wage)+(#machines down)(cost of machine being down)

Using our notation above, we have:

COST = R*W + Md*L

Md is the average number of machines down at any one time. This depends on how many technicians are working. We must find Md to figure out the cost. Unfortunately, finding Md is the most difficult part! We must calculate the probability of different numbers of machines being down and then we can find the average number of machines down.

To find Md:

Let n=the number of machines down. Queuing theory lets us calculate probability using:

P(n+1)=probability that n+1 machines are down

P(n)=probability that n machines are down.

If n

If R<=n<=N then P(n+1)=T*((N-n)/R)*P(n)

For example, if N=50 (we have 50 machines in the shop), R=5 (we have 5 technicians), and T=.05 (traffic intensity), then using the equations above, we get:

P(1)=T*N*P(0) =2.5P(0) and this is the probability that one machine is down

P(2)=.5*T*(N-1)*P(1) =1.225P(1) =3.063P(0) prob that two machines are down

P(3)=.33*T*(N-2)*P(2) =.792P(2) =.970P(1) =2.43P(0) prob that 3 machines are down

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P(6)=T*(N-5)/R*P(5) =.450P(5) =.298P(0) prob that 6 machines are down

Ok, so we need to find P(0), then we can use this to find the rest.

Set P(0)=1(there is statistical theory behind this but its beyond the scope of this class)

Calculate the probabilities for all n, up to N, usingP(0)=1(do what we just did above but P(0) will be equal to 1).

Sum all the probabilities up to N.

Multiply each n*P(n)

Sum all n*P(n)

Finally, Md=(sum of n*P(n))/(sum of P(n)),that is Md=(step e)/(step c)

Now that we know Md, we just calculate the cost using the formula for total cost on the first page.

DETAILS: We will consider two types of technicians (fast and slow) and two types of machines (good and poor). This means we have four possible combinations:

fast technician and good machines

fast technician and poor machines

slow technician and good machines

slow technician and poor machines

This means that for each case above, we are trying to find R the number of technicians we should hire.

Heres a quick algorithm for solving the problem:

The user will input the following data:

Number of machines, cost of inoperable machines, maximum number of technicians,

Failure rate for good machine, failure rate for poor machine, hourly wage for fast tech,

Hourly wage for slow tech, repair rate for fast tech, repair rate for slow tech

Do Case 1 (ie. fast workers and good machines)

Calculate T

For each value of R, up to the maximum

Calculate Md (using procedure outlined above)

Calculate Total Cost using formula above

Find the optimum number of technicians to hire for that case (ie.This will be the minimum cost).

Do Case 2 (fast workers, poor machines)

You must do steps 2-5 all over again using the appropriate numbers for fast workers and poor machines)

Continue for next two cases.

OUTPUT REQUIRED: Your output should look like this:

BASIC PARAMETERS:

Downtime loss per machine = $XXX.XX

Total number of machines=XXX

Types of technicians: Fast Slow

Corresponding wages $XX.XX/hr $XX.XX/hr

And repair rates .XXX/hr .XXX/hr

Types of machines: Good Poor

Fail Rates .XXX/hr .XXX/hr

Type of Type of Traffic Optimum Total

Worker machine intensity number Cost

Fast good X.XXX XX $XXXX.XX

Fast poor X.XXX XX $XXXX.XX

Slow good X.XXX XX $XXXX.XX

Slow poor X.XXX XX $XXXX.XX