C$++$ write a program that prints the day number of the year, given the date in the form month$-$day$-$year. For example, if the input is $1-1-2006,$ the day number is $1$; if the input is $12-25-2006,$ the day number is $359.$ The program should check for a leap year. A year is a leap year if it is divisible by $4,$ but not divisible by $100.$ For example, $1992$ and $2008$ are divisible by $4,$ but not by $100.$ A year that is divisible by $100$ is a leap year if it is also divisible by $400.$ For example, $1600$ and $2000$ are divisible by $400.$ However, $1800$ is not a leap year because $1800$ is not divisible by $400.$

Your program must define and use the following functions:

isLeapYear $-$ This function must accept the year as an argument. It must return true if the year is a leap year and false if it is not a leap year.

determineDaysInMonth $-$ This function must accept the month and year as arguments. It must return the number of days in the month. Beware of leap years! Hint: A switch would be very useful here.

computeDayofYear $-$ This function must accept the month, day, and year as arguments. It must return the day number of the year.

print $-$ This function will accept the day number of the year and the year as arguments. It must print the day number of the year with explanatory text. It will not return a value.