Question: c [ ( x y + 2 ) + j ( x y - 2 ) ] d z C 1 line between ( 0

c[(xy+2)+j(xy-2)]dz
C1 line between (0,1)
and (3,-1)
Hu(2):-Cz2dz
c2:y=x2+3,(0,3)(1,4)
hints 13=((0)c,3
You can say wecande
x=y-32 this
dydx=2x
dy=2xdx
dx=dy2x
c [ ( x y + 2 ) + j ( x y - 2 ) ] d z C 1 line

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