Calc 2 :

Section 8.5: Problem 1 (1 point) Consider the power series (9r)" IM The interval of convergence goes from r = to C = The radius of convergence is R = If needed, enter INF for co and -INF for -co.Section 8.5: Problem 2 {1 point] Consider The power series: 411:\" 2'1) Qis2 i 5) lI7l='.|. The interval of convergence goes from m = C] to :I: = C]. The radius of convergence is R = E] if needed, enter iNF for on and iNF for 00. Section 8.5: Problem 3 (1 point) Consider the series: DO E (-1)"20 n=1 Vn + 5 The interval of convergence goes from I = to C = The radius of convergence is R = If needed, enter INF for oo and -INF for -0o.Section 8.5: Problem 4 (1 point) Consider the power series: (Ex - 7) n=1 n(-5) The interval of convergence goes from I = to = The radius of convergence is R = 5 If needed, enter INF for oo and -INF for -co.Section 8.5: Problem 5 (1 point) Consider the series: DO E n' (r +9)" n=1 The interval of convergence goes from T = to C = The radius of converge is R = 9 If needed, enter INF for oo and -INF for -0o.Section 8.5: Problem 8 (1 point) Consider the series: DO 7"(r" ) (n + 1) n=1 (n + 5) The interval of convergence goes from r = to I = The Radius of convergence is R = If needed, enter INF for co and -INF for -0o