Calculate the activity in millicuries of 123I produced by the 121Sb (, 2n) 123I reaction, when 200-mg natural antimony (natural abundance of 121Sb is 57.3%) is irradiated for 2 h with an -particle beam of 25-MeV energy and an intensity of 1014 particles/(cm2.s). The cross-section for formation of 123I (t1/2 = 13.2 h) is 28 mbarns.

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To solve this problem well first determine the activity produced in curies then convert it to millic... View the full answer