Calculate the attractive force between two parallel plates in a parallel$-$force electrostatic actuator. The width of each plate is $200\mathrm{.}0$ m$,$ the separation distance between the plates is $2\mathrm{.}500$ m and the applied voltage is $0\mathrm{.}3500$ V$.$ The relative permittivity of the air between the plates is $1\mathrm{.}0006,$ while the vacuum permittivity is $8\mathrm{.}8541012$ F m$1.$