Question: Calculate the average H 0 rxn from the two runs. [NaOH] / mol L -1 : 0.9996 [HCl] / mol L -1 : 1.0011 HCl(aq)

Calculate the average H0rxn from the two runs.

[NaOH] / mol L-1: 0.9996

[HCl] / mol L-1: 1.0011

HCl(aq) + NaOH(aq) ---> NaCl(aq) + H2O(l)

run #1. final mass= 104.76g. Calculate the average H0rxn from the two runs. [NaOH] / mol L-1:T=6.00K. qcontents= -2543.54J

Run #2. final mass= 98.29g. 0.9996 [HCl] / mol L-1: 1.0011 HCl(aq) + NaOH(aq) ---> NaCl(aq) +T= 6.40K. qcontents=-2631.97J

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