Calculate the derivative

$\frac{d}{dx}{\displaystyle \underset{-1}{\overset{x}{}}}(5t^3-t{)}^{22}dt$

using Part $2$ of the Fundamental Theorem of Calculus.

$\frac{d}{dx}{\displaystyle \underset{-1}{\overset{x}{}}}(5t^3-t{)}^{22}dt=$

$$Calculate the derivative

$\frac{d}{dx}{\displaystyle \underset{-1}{\overset{x}{}}}(5t^3-t{)}^{22}dt$

using Part $2$ of the Fundamental Theorem of Calculus.

$\frac{d}{dx}{\displaystyle \underset{-1}{\overset{x}{}}}(5t^3-t{)}^{22}dt=$

$$