Calculate the given integral: ${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}ta{n}^4(9x)dx$

$\frac{1}{27}ta{n}^3(9x)-\frac{1}{9}tan(9x)+x+C$

$\frac{1}{18}ta{n}^2(9x)+\frac{1}{9}ln|cos(9x)|+C$

$\frac{1}{27}ta{n}^3(9x)+\frac{1}{9}tan(9x)+9x+C$

$\frac{1}{18}ta{n}^2(9x)-\frac{1}{9}ln|cos(9x)|+C$

$\frac{1}{18}ta{n}^2(9x)+\frac{1}{9}sec(9x)+C$