Question: Calculate the number of milliliters of 0.753 M KOH required to precipitate all of the Pb2* ions in 135 mL of 0.775 M Pb(NO3)2 solution

Calculate the number of milliliters of 0.753 M KOH required to precipitate all of

the Pb2* ions in 135 mL of 0.775 M Pb(NO3)2 solution as Pb(OH)2. The equation for the reaction is: Pb(NO3)2(aq) + 2 KOH(

the Pb2* ions in 135 mL of 0.775 M Pb(NO3)2 solution as Pb(OH)2. The equation for the reaction is: Pb(NO3)2(aq) + 2 KOH(aq) Pb(OH)2(s) + 2 KNO3(aq)

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