Calculate the surface area of the solid generated by revolving y = sin(x)and x = 2 and

x = 0 about the x -axis

a)4(sqrt(2) + sinh^(-1)(1)) 28.8472

b)2(sqrt(2) + sinh^(-1)(1)) 14.4236

c)(sqrt(2) + sinh^(-1)(1)) 7.2118

d) undefined

\int_a^b 2\pi y\sqrt(1+((dy)/(dx))^(2)) dx

(revolved around the x-axis)

Hint: Surface area y = sin(x) for 0