Question: Calculus 2 Please type the Answer 2. [0/1 Points] DETAILS PREVIOUS ANSWERS SCALCET9 7.XP. 1.012.MI. 4/100 Submissions Used MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER

Calculus 2

Please type the Answer

Calculus 2 Please type the Answer 2. [0/1 Points]Calculus 2 Please type the Answer 2. [0/1 Points]Calculus 2 Please type the Answer 2. [0/1 Points]Calculus 2 Please type the Answer 2. [0/1 Points]Calculus 2 Please type the Answer 2. [0/1 Points]
2. [0/1 Points] DETAILS PREVIOUS ANSWERS SCALCET9 7.XP. 1.012.MI. 4/100 Submissions Used MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER Evaluate the integral. (Use C for the constant of integration.) 5x cos(2x) dx 5x sin 2x + 5 cos 2x + C 2 4 X Enhanced Feedback Please try again. Recall that / u dv = uv - / v du. Try letting u = x and dv = cos(kx) dx. Need Help? Read It Watch It Master It Submit Answer3. [0/1 Points] DETAILS PREVIOUS ANSWERS SCALCET9 7.XP. 1.016. 1/100 Submissions Used MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER Evaluate the integral. (Use C for the constant of integration.) ( x - 6 ) sin ( TX ) dx sin x - T(x - 6 ) cos TX + C X Need Help? Read It Submit Answer7. [0/1 Points] PREVIOUS ANSWERS SCALCET9 7.1.023.M|. ill 00 Submissions Used Evaluate the integral. (Use Cfur the constant of integration.) ASK YOUR TEACHER PRACTICE ANOTHER fess sin(98) d5 1 ( 86 . 86 ) e Sln a9 e cos 6 145 s 9 9 9 0 X :Enhanced Feedback Please try again. Recall that f u dv : uv f v d\". l : ry using integration by parts twice, thus repeating the same integral. Once you've repeated the integral, move both instances of it to one side of the equation and solve for it. 1 Need Help? Submit Answer 8. [0/1 Points] DETAILS PREVIOUS ANSWERS SCALCET9 7.1.025. 1/100 Submissions Used MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER Evaluate the integral. (Use C for the constant of integration.) 1923ez dz 19[2.=3 - 3e2 .=2 + be? = -602 + C] X Need Help? Read It Watch It Submit Answer10. [0/1 Points] DETAILS PREVIOUS ANSWERS SCALCET9 7.1.032. 1/100 Submissions Used MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER Evaluate the integral. w2 In ( w ) dw [343 In(3) - 144] X Need Help? Read It Submit

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