calculus.......

. dy . (1.1.4 reVised) Solve (127 2 $2 _ 1, 1 . (1.1.102) Solve a." 2 312, 33(1) 2 1. for y(0) 2 0. Find its maximal interval of existence. . (1.2.3) Sketch slope eld for y' 2 3,12. . (1.2.5) Is it possible to solve the equation y' 2 y\\/|:c| for y(0) 2 0? Is the solution unique? Justify. . (1.2) Find at least two solutions y1(t) and y2(t) of 9'05) = 291/2. 9(0) = 0. for t 2 0. Explain why the existence of two solutions of the given problem does not contradict the uniqueness part of Theorem 1.2.1. . (1.3.3) Solve 25: 2 (332 1)t, for 23(0) 2 0