Question: calculus problem A particle is moving along a curve C with acceleration equal to (1'05) = 862t sin 2ti + 46%} + 88% cos 2t
calculus problem

A particle is moving along a curve C with acceleration equal to (1'05) = 862t sin 2ti + 46%} + 88% cos 2t 1} at any time t > 0. Suppose that the particle 13 at the point (1, 1, 0) and moving with velocity 17(23 ) 2i+2j +2k at time t 0. (a) Find the velocity 11(15), speed 2103), and position t) of the particle. [8 marks] (b) Calculate the tangential and centripetal components (IT and (IN of the particle's acceleration from the velocity and acceleration of the particle. [7 marks] (Hint: Use the integral formulas for any real numbers or and [3: 1,1 in = eatiasinwti Beams] [e s (t) dt (012+B2) at _ eatl silt) + 0% COSWH /e cos(t)dt (a2 + 52) . l
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